ABCD is a parallelogram in which angle A = 108 degrees Calculate angles B, C and D.

Answers (1)
S safeer

Opposite angles of a parallelogram are equal

<A=<C =108 and let <B=<D=a

We know that sum of the interior angles of a quadrilateral is 360. That is

2 x 108 + 2a=360

2a=360-2 x 108

2a= 360=216

2a=144

a=72

So B=D=72 and C=108

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