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A chord of a circle of radius 14 cm subtends an angle of 60o at the center. Find the area of the corresponding minor segment of the circle. \left(\text{Use } \pi = \frac{22}{7} \text{ and }\sqrt{3} = 1.73 \right )

 

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Radius = 14 cm

Angle = 60o

Area of segment is given by = \frac{\theta}{360} \pi r^2

Aera of minor segment   = \frac{60\degree}{360\degree} \pi (14)^2

                                             = 102.65 cm^2

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Safeer PP

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