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  • An electron microscope uses electrons accelerated by a potential difference 50 kV. Calculate the de Broglie wavelength of the electrons. Compare the resolving power of an electron microscope with that of an optical microscope, which uses visible light

An electron microscope uses electrons accelerated by a potential difference 50 kV. Calculate the de Broglie wavelength of the electrons. Compare the resolving power of an electron microscope with that of an optical microscope, which uses visible light of wavelength 550 nm. Assume the numerical aperture of the objective lens of both microscopes are the same.

 

 

 

 
 
 
 
 

Answers (1)

Wavelength,

\lambda =\frac{h}{\sqrt{2meV}}=\frac{6.6\times 10^{-31}}{\sqrt{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-9}\times 50\times 10^{3}}}

     =5.47\times 10^{-12}m

Resolving power of a microscope is inversely proportional to the wavelength of light used.

The wavelength of the accelerated electron is 10^{5} times that of given wavelength (550 nm) 

\therefore Resolving power of the electron microscope is \simeq 10^{5} that of optical microscope.

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Safeer PP

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