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Construct a \triangle ABC in which CA=6cm and AB=5cm and \angle BAC =45^{\circ}. Then construct  a triangle whose sides are \frac{3}{5} of the corresponding sides of \triangle ABC.

 

 
 
 
 
 

Answers (1)

Step-1: Draw a line of 5cm with scale MN and also draw an arc with help of point A.

Step-2:

Make another arc using the same distance which was taken in first step but the arc from point O.

Step-3:

Join Point PN.

Now, for corresponding triangles,

Step-1: Draw a ray NX making an acute angle with PN on the opposite side of vertex M.

Step-2: Cut line NQ into 5 equal parts from point N.

Step-3: Connect point AE and Construct an acute angle to PEN.

Step-4: Draw line parallel to MP from point x1.

\triangle X_2NX_1 is the corresponding triangle where length is 3/5th of the given triangle.

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