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Construct a triangle ABC with side BC = 6 cm, AB = 5 cm and \mathrm{\angle ABC = 60\degree}. Then construct another triangle whose sides are \frac{3}{4} of the corresponding side of triangle ABC.

 

 

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Given

    In \DeltaABC

    BC = 6cm,    \angleB = 60\degree and AB = 5 cm

  1. Draw a line segment BC = 6cm and draw a ray which makes an angle of 60\degree with BC
  2. Draw an arc of radius 5cm from B so that it cuts Ray BX at A.
  3. Join AC to get \DeltaABC
  4. Draw a ray by moving an acute angle with BC opposite to A.
  5. Locate four points B1, B2, B3, and B4 in such a way \mathrm{BB_1 = B_1B_2 = B_2B_3 = B_3B_4}
  6. Join B4C and draw a line from point B3 parallel to B4C so that it cuts BC at C'.
  7. From point C' draw a line parallel to AC and cuts AB at A'.
  8. \DeltaA'BC' is the required triangle.

 

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