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Construct an isosceles triangle whose base is 8\; cm and altitude 4\; cm and then another triangle whose sides are \frac{3}{4} times the corresponding sides of the isosceles triangle

 

 

Answers (1)

First we need to construct an isosceles \Delta ABC where ba is 8\: cm and altitude =4\: cm

Then we have to attend the \Delta ABC to make a triangle which is \frac{3}{2} of \Delta ABC

Steps for construction =

(i) Draw a line of 8\: cm using scale name it BC

(ii) Draw a \perpdirection using compars.

(iii) now take O as centre, make 4\; cm on the direction like.

(iv) join the point wih B and C.

(V) we will get isosceles \Delta ABC

Scale factor =\frac{3}{2}

(Vi) Now to make a \Delta which is \frac{3}{2}\Delta ABC, draw a ray BX which is making an acute angle with BC 

(Vii) Make 3 points on BX (B_{1},B_{2},B_{3}) such that BB_{1}=B_{1}B_{2}=B_{2}B_{3}

(viii) Join B_{2}C and draw a line B_{3} parallel to B_{2}C to intersect BC extended at C'.

(ix) Draw a line through C' parallel to the line AC to intersect AB extended at A'.

(x) We will get \Delta AB'C' which is \frac{3}{2}\; \Delta ABC

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Safeer PP

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