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Find the coordinates of a point A, where AB is a diameter of the circle with centre (-2,2) and B is the point with coordinates (3,4).

 

 

Answers (1)

Given

        Coordinates of circle = (-2,2)

        Coordinates of B        = (3,4)

Since AB is the diameter of circle

Let (x,y) be the coordinates of point A.

Centre of the circle is the midpoint of AB.

    \therefore (-2,2) = \left[\left(\frac{x+3}{2} \right ),\left(\frac{y+4}{2} \right ) \right ]

    \Rightarrow \left(\frac{x+3}{2} \right ) = -2

    \Rightarrow x = -7

    and

    \Rightarrow\left(\frac{y+4}{2} \right ) = 2

    \Rightarrow y = 0

So, A(-7, 0) is the required coordinates.    

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Safeer PP

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