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  • Find the coordinates of a point A, where AB is diameter of circle whose centre is (2,-3) and B is the point (1,4).        

Find the coordinates of a point A, where AB is diameter of circle whose centre is (2,-3) and B is the point (1,4).

 

 

 

 
 
 
 
 

Answers (1)

Given -> Coordinates of centre O is (2,-3) & coordinates of point B is (1,4).

To find -> Coordinates of point A.

Solution-> We have drawn a circle with centre O where AB is the diameter of the circle.

Let's assume the coordinates of A=(x,y)

We know AB is the diameter of the circle, O must be the midpoint of AB.

 \therefore X \: Coordinate\: of \: O\, = \frac{x+1}{2}

\therefore 2 = \frac{x+1}{2}

\therefore 4 = {x+1}

\therefore x = 3

\therefore y \: Coordinate\: of \: O\, = \frac{y+4}{2}

\therefore -3 = \frac{y+4}{2}

\therefore -6 = {y+4}

\therefore y = -10

Hence the coordinates of poin A = (3,-10)

 

Posted by

Safeer PP

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