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Find the equation to the straight line which passes through the point (-5,4)and is such that the portion of it between the axes is divided by the point inthe ratio of 1:2

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Answer: 

Let the requried straight line be \ x/a +y/b=1 .this meets the axes in the point whose coordinate are(a,0);and (0,b)

     The coordinates of the point dividing the line joining these points in the ratio 1:2 , are

\ (2 imes a+1 imes 0)/3 ; and ; (2 imes 0+1 imes b)/3

i.e ,\2a/3 ; and ; b/3

if this be the point (-5,4) we have 

\ -5=2a/3;and; 4=b/3\ \Rightarrow a=-15/2 ; b =12

The requried straight line is

\ Rightarrow x/-15/2+y/12=1\ \Rightarrow 5y-8x-60=0

 

Posted by

Deependra Verma

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