Find the value of k so that the area of triangle ABC with A(k + 1, 1), B(4, – 3) and C(7, – k) is 6 square units.
Here the area of triangle ABC with A(k + 1, 1), B(4, – 3) and C(7, – k) is 6 square units.
Take
Take
So, it doesn't have real roots.