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Find the value(s) of k for which the pair of equations \left\{\begin{matrix} kx+2y= 3\\ 3x+6y= 10 \end{matrix}\right. has a unique solution.

 

 

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Given      pair of equations kx+2y= 3 ---(i)
                                           3x+6y= 10 ---(ii)
For unique solutions of pair of equations
 a_{1}x+b_{1}y= c_{1}
a_{2}x+b_{2}y= c_{3}
\frac{a_{1}}{a_{2}}\neq \frac{b_{1}}{b_{2}}
Hence , \frac{k}{3}\neq \frac{2}{6}
\Rightarrow k\neq \frac{2}{6}\times 3
\Rightarrow k\neq 1
k can take any real value except 1
 

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Safeer PP

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