For a 5% solution of urea (Molar mass = 60 g/mol), calculate the osmotic pressure at 300 K. [R = 0·0821 L atm K-1 mol-1]

 

 

Answers (1)
S safeer

Given,

5% urea solution means 5g urea is present in 100ml of solution.

moles of urea present =weight given/Molecular weight of urea

                                   =5g / 60gmol−1=112

Hence Concentration of urea = (moles of urea(n) /volume of solution ) ×1000

={(112)/100}∗1000

=1012

Hence Osmotic pressure =1×(10/20)×0.082×300 atm

=20.52atm

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