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  • For a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 K is 2 V.If the current amplification factor of the transistor is 100, calcula

For a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 K\Omega is 2 V.If the current amplification factor of the transistor is 100, calculate the input signal voltage and the base current, given the base resistance as 1\Omega.

 

 

 

 
 

Answers (1)

Given that
         Out put voltage  = 2V
         collector resitance = 2K\Omega
Current Amplifiction factor \beta = 100
Base Resistance = 1K \Omega
Collector current I_{c}= \frac{V_{0}}{R_{0}}
                             = \frac{2}{2\times 10^{3}}= 1\times 10^{-3}A
                                                  = 1mA
We know \beta = \frac{i_{c}}{i_{b}}
Therefore, i_{b}= \frac{i_{c}}{\beta }= \frac{1\times 10^{-3}}{100}= 1\times 10^{-5}A
Base current   i_{b}= 10mA 
Input voltage signal V_{BE}= i_{b}\times R_{b}
                                      = 1\times 10^{-5}\times 1\times 10^{3}= 10^{-2}V
Hence, Input signal voltage is 10mV and Base current is 10mA 

Posted by

Safeer PP

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