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In Fig. 4 AB is a chord of circle with centre O, AOC is diameter and AT is tangent at A. Prove that \angleBAT = \angleACB.   

 

 
 
 
 
 

Answers (1)

<BAC = 90° – < BAT.....(1)
In triangle BAC, < B = 90°
So,< BCA = 90° – < BAC
or ∠ ACB = ∠ BAT from (1)

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