Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • In Figure 2, PQ is a chord of length 8 cm of a circle of radius 5 cm. The tangents at P and Q intersect at a point T. Find the length TP.

In Figure 2, PQ is a chord of length 8 cm of a circle of radius 5 cm. The tangents at P and Q intersect at a point T. Find the length TP.

 

 
 
 
 
 

Answers (1)

Let the value of TR be x and TP be y cm.

OT is \perp bisector of PQ.

So, PR = QR = 4cm

In \DeltaOPR

        \mathrm{OP^2 = PR^2 + QR^2}

        \mathrm{5^2 = 4^2 + QR^2}

    \mathrm{\Rightarrow QR= 3}

In \DeltaPRT     \mathrm{y^2 = x^2 + 4^2\qquad - (i)}

In \DeltaOPT    \mathrm{(x+3)^2 = 5^2 + y^2}

\mathrm{\Rightarrow (x+3)^2 = 5^2 + x^2 + 4^2\quad [From \ eq(i)]}

\mathrm{\Rightarrow x = \frac{16}{3}cm}

Put value of x in eq(i)

so,    \mathrm{y = \frac{20}{3}cm}

\mathrm{TP= \frac{20}{3}cm}

Posted by

Safeer PP

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 10, 12 syllabus 2024-25 out; board restores two-level mathematics rule
anam-khan

CBSE Class 10 board exam 2024 passing criteria, eligibility for compartment; all you need to know

Latest Question