Prove that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Given in the question,
A right-angled triangle ABC in which
To prove:- (hypotenuse)2 = (base)2 + (perpendicular)2
Construction
Proof: In ADB and ABC
So, By AA-similarity criterion
In and
So, by AA-similarity
Adding eq (i) and (ii)
Hence