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  • Show how would you join three resistors, each of resistance  so that the equivalent resistance of the combination is (i)

Show how would you join three resistors, each of resistance 9\; \Omega so that the equivalent resistance of the combination is

(i) 13.5\; \Omega

(ii) 6\; \Omega ?

 

 

 

 
 
 
 
 

Answers (1)

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Case 1 : To get equivalent resistance =13.5\; \Omega for this case two 9\; \Omega resistors should be first connected in parallel and then their combination should be connected in series with remaining 9\; \Omega resistors,Thus

R=\frac{9\times 9}{9+9}=\frac{81}{18}=4.5\Omega

R_{total}=R+9=4.5+9=13.5\; \Omega

(2) Case 2 : To get equivalent resistance = 6\; \Omega for this case two 9\; \Omega resistors should be irst connected in series and then this combination should be connected in parallel with remaining 9\; \Omega resistors, Thus,

R_{1}=9+9=18\; \Omega

R_{total}=\frac{R_{1}\times R}{R_{1}+R}=\frac{18\times 9}{18+9}=6\; \Omega

 

 

Posted by

Sumit Saini

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