# solve this: 3x - 7 > x + 1

$3x-7>x+1\\*Given:3x-7>x+1\\*\Rightarrow 3x-7+7>x+1+7\\*\Rightarrow 3x>x+8\\*\Rightarrow 3x-x>x+8-x\\*2x>8\\*Divide\;both\;sides\;by\;2, \;we\; get\\*\Rightarrow \frac{2x}{2}>\frac{8}{2}\\*\Rightarrow x>4\\*\therefore\;The\; solution\;of\;the\;given\;inequation\;is\;(4,\infty)$

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