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  • The ages of Leena and Heena are in the ratio 7:5 . Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.

The ages of Leena and Heena are in the ratio 7:5 . Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.

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 Expert
Ages of leena and heena ratio is 7 : 5 , 
ten yrs hence therir ages as 9 : 7 
therefore (9x + 10) / 7x+10 = 7/5
cross multiply we get
45x + 50 = 49x + 70
49x - 45x = 70 - 50
4x = 20
x = 5
their present ages 9x+ 10 = 9 (5) + 10 = 55
7x+ 10 = 7(5) + 10 = 45
their ages are 55,45

Posted by

Satyajeet Kumar

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