The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

Answers (1)

Let the ages of the three persons be 4x, 7x and 9x
Let the ages of the three persons 8 YEARS ago be 4x-8, 7x-8 and 9x-8
according to the question, 
4x-8+7x-8+9x-8=56
20x-24=56
20x=56+24
20x=80
x=80/20
x=4
Therefore, present ages are 16,28 and 36.

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