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  • What volume of 6M HCl and 2M HCl should be mixed to get one litre of 3M HCl?

What volume of 6M HCl and 2M HCl should be mixed to get one litre of 3M HCl?

Answers (1)

Suppose the volume of 6M HCl required to prepare 1 L of 3M HCl = x L

Volume of 2M HCl required = (1-x) L

Apply molarity equation

M1V1 + M2V2 = M3V3

6 × (x) + 2 ( 1-x) = 3 x 1

6x + 2 - 2x = 3

4x +2 = 3

4x = 3 - 2

4x = 1

x = 1/4 = 0.25 L

so volume of 6M HCl required = 0.25 L

volume of 2M HCl required = 1 - 0.25 = 0.75 L

Posted by

Ankit Dutt

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