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  • A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be not green?

9.(iii)    A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at               random. What is the probability that the marble taken out will be not (iii) green?

Answers (1)

best_answer

Given,

Total number of balls in the bag = 5 + 8 + 4 = 17

(iii) Let G be the event that the ball taken out is green

The number of possible outcomes = 17 

The number of outcomes favourable to the event G = 4

\therefore P(G) = \frac{favourable\ outcomes}{total\ outcomes}=\frac{4}{17}

\\ \therefore P(not\ G) =P(\overline G) =1-P(G) \\ = 1-\frac{4}{17} \\ = \frac{13}{17}

The required probability of not getting a green ball is \frac{13}{17}

Posted by

HARSH KANKARIA

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