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A man accepts a position with an initial salary of Rs 5200 per month. It is understood that he will receive an automatic increase of Rs 320 in the very next month and each month thereafter.

(a) Find his salary for the tenth month
(b) What is his total earnings during the first year?

Answers (1)

The man’s salary in first month is Rs. 5200 and increases every month by Rs. 320. So, we have the value of ‘a’ and ‘d’.

t_{n}=a+ \left( n-1 \right) d

Salary in 10th month is given by t_{10}=5200+ \left( 10-1 \right) 320=8080

For total earnings in first year, the first 12 terms of the sequence are added.

S_{n}= \left( \frac{n}{2} \right) \left( 2a+ \left( n-1 \right) d \right)

S_{12}= \left( \frac{12}{2} \right) \left( 2 \left( 5200 \right) + \left( 12-1 \right) 320 \right)

S_{12}=6( 10400+11 \left( 320 \right) =83520

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