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  • A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 L (measured at STP) of this welding gas is found to weigh 11.6 g. (iii)

1.34    A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 L (measured at STP) of this welding gas is found to weigh 11.6 g. Calculate

 (iii) molecular formula.

Answers (1)

best_answer

As we know the empirical formula from the previous part is CH.

The mass of empirical formula CH = 12+1 =13.

Therefore, 

n = \frac{Molecular\ Mass}{Empirical\ Formula}

\Rightarrow \frac{26}{13} =2

Therefore, Molecular formula is C_{2}H_{2}.

Posted by

Divya Prakash Singh

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