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1. ABC is an isosceles triangle with $AB=AC$ (Fig 7.17). Take a trace-copy of $\Delta ABC$ and also name it as $\Delta ABC$
            (i) State the three pairs of equal parts in $\Delta ABC \; and \: \Delta ACB$ .
            (ii) Is $\Delta ABC \cong \Delta ACB$ ? Why or why not?
            (iii) Is $\angle B = \angle C$ ? Why or why not?

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best_answer

Here, in $\Delta ABC \; and \: \Delta ACB$ .

i)the three pairs of equal parts in $\Delta ABC \; and \: \Delta ACB$ are

AB = AC

BC = CB

AC = AB

ii)

Hence By SSS Congruency rule, they both are congruent.

$\Delta ABC \cong \Delta ACB$

iii) Yes, $\angle B = \angle C$ because $\Delta ABC \; and \: \Delta ACB$ are congruent and by equating the corresponding parts of the triangles we get,

$\angle B = \angle C$ .

Posted by

Pankaj Sanodiya

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