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An amorphous solid “A” burns in air to form a gas “B” which turns lime water milky. The gas is also produced as a by-product during roasting of sulphide ore. This gas decolourises acidified aqueous KMnO_{4}  solution and reduces Fe^{3+} to Fe^{+2}. Identify the solid “A” and the gas “B” and write the reactions involved.

 

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A is sulphur (S_{8}) while B is sulphur dioxide (SO_{2}).

S_{8}+8O_{2}\rightarrow 8SO_{2}

2ZnS+3O_{2}\rightarrow 2ZnO+2SO_{2}

2KMnO_{4}+3H_{2}SO_{4}\rightarrow K_{2}SO_{4}+2MnSO_{4}+3H_{2}O+5\left [ O \right ]

\left [ SO_{2}+\left [ O \right ]+H_{2}O\rightarrow H_{2}SO_{4} \right ]\times 5

2KMnO_{4}+3H_{2}SO_{4}\rightarrow K_{2}SO_{4}+2MnSO_{4}+2H_{2}SO_{4}

 

SO_{2}+2H_{2}O\rightarrow H_{2}SO_{4}+2\left [ H \right ]

Fe_{2}\left ( SO_{4} \right )_{3}+2\left [ H \right ]\rightarrow 2FeSO_{4}+H_{2}SO_{4}

Fe_{2}\left ( SO_{4} \right )_{3}+SO_{2}+2H_{2}O\rightarrow 2FeSO_{4}+2H_{2}SO_{4}

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