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7.

(b) Find $x + y + z + w$

Answers (1)

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Here you will find the detailed solution of the above-written question,

$x+120\degree = 180\degree$

$x=180\degree - 120\degree$

$x=60\degree$

$y+80\degree = 180\degree$

$y=180\degree - 80\degree$

$y=100\degree$

$z+60\degree = 180\degree$

$z=180\degree - 60\degree$

$z=120\degree$

Sum of all angles of quadrilateral = $360\degree$

Let the unmarked angle be A.

$A+120\degree+60\degree+80\degree=360\degree$

$A=100\degree$

$A+w=180\degree$

$w= 80\degree$

$x + y + z + w$ = $60\degree+100\degree+120\degree+80\degree$

$x + y + z + w$ = $360\degree$

Posted by

seema garhwal

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