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  • Check what the result would have been if Sundaram had chosen the numbers shown below. 1. 417

Check what the result would have been if Sundaram had chosen the numbers shown below.   

    Q1. 417

Answers (1)

best_answer

Let chosen number be abc then,

abc = 100a + 10b + c

cab = 100c + 10a + b

bca = 100b + 10c + a

After adding all the above three, abc + cab + bca = 111(a + b + c) = 37 × 3(a + b + c),

It will be divisible by 37 because 37 is present in the equation.

here a = 4, b = 1, and c = 7

417 + 741 + 147 = 1332 = 37*36  i.e. divisible by 37.

Posted by

Pankaj Sanodiya

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