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  • Check what the result would have been if Sundaram had chosen the numbers shown below. 3. 117

Check what the result would have been if Sundaram had chosen the numbers shown below.

    Q3. 117

 

Answers (1)

best_answer

Let chosen number be abc then,

abc = 100a + 10b + c

cab = 100c + 10a + b

bca = 100b + 10c + a

The addition of the above all three, abc + cab + bca = 111(a + b + c) = 37 × 3(a + b + c), which is divisible by 37

here a = 1, b = 1, and c = 7

117 + 711 + 117 = 999 = 37*27  i.e. divisible by 37.

Posted by

Pankaj Sanodiya

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