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Q : 3          Consider, the special case of Identity (IV) with a=-c and b=-c What do     
                  you get? Is it related to Identity (II)? 

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Identity IV is \Rightarrow (a+x )(b +x) = x^{2} + (a+b)x + ab
If a = b = -c  than,
                          (x - c)(x - c) = x^{2} + (-c + (-c))x + (-c) \times (-c)
                           (x-c)^{2} = x^{2} + -2cx + c^{2}
    Which is identity II

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Gautam harsolia

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