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  • Construct a triangle PQR in which QR = 6cm, ∠Q = 60° and PR – PQ = 2cm.

Q3.    Construct a triangle PQR in which QR = 6cm, \angle Q = 60 \degree and PR -PQ = 2cm.

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The steps of construction to be followed:

Step 1: Draw a ray QX and cut off a line segment QR which is equal to 6 cm in length.

Step 2: With an angle of 60^{\circ} with QR, construct a ray QY and extend it to form a line YQY'.

Step 3: Now, cut off a line segment QS equal to 2 cm from QY' and join RS.

                                             Y 

s2

   Y'

 

 

Step 4: Draw a perpendicular bisector of RS which intersects QY at a point P.

Step 5: Join PR to get the required triangle \triangle PQR.

Posted by

Divya Prakash Singh

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