Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Construct the following quadrilaterals. (iii) Rhombus BEND BN = 5.6 cm DE = 6.5 cm

Q1. Construct the following quadrilaterals.

(iii) Rhombus BEND
BN = 5.6 cm
DE = 6.5 cm

Answers (1)

best_answer

Given, BEND is a rhombus.

BN = 5.6 cm (Diagonal)
DE = 6.5 cm (Diagonal)

We know that the diagonals of a rhombus bisect (cut in halves) each other at 90 degrees.

Steps of construction: 

Step 1.  Draw a line segment BN = 6.5 cm. With radius greater than half of BN, draw arcs on both sides of BN with B and N as the center. The line joining these two intersections is the perpendicular bisector of BN. Let it intersect BN at O (Therefore, O is the midpoint of BN. It will also be the midpoint of DE!)

 Step 2.  With O as the center, draw two arcs on the perpendicular bisector with radius = \frac{1}{2} DE = \frac{6.5}{2} = 3.25 cm  (Since, O is the midpoint of DE.)

Step 3. The intersecting points are vertices D and E.

Step 4. Join D to B and N. Also join E to B and N.

BEND is the required rhombus.

Posted by

HARSH KANKARIA

View full answer

Similar Questions

Trending Articles/News

anam-khan

JNVST 2025 Class 6 registration ends today; apply at navodaya.gov.in

Latest Question