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  • Construct ∆PQR if PQ = 5 cm, m∠PQR = 105° and m∠QRP = 40°.

Q 2.     Construct \Delta PQR if PQ = 5 cm, m\angle PQR = 105^{\circ} and m\angle QRP = 40^{\circ}.

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\Delta PQR if PQ = 5 cm, m\angle PQR = 105^{\circ} and m\angle QRP = 40^{\circ}:

the sum of angles of a triangle is 180 degrees. Given angles PQR and QRP, so the angle QPR= 180-(105+40)=35 degrees

1. Draw the line PQ=5 cm 

2. At Q making an angle 105 degrees with PQ draw a line QY

3. At P making an angle 35 degrees with PQ draw a line PX

4. The lines PX and QY intersect at R ( in case the drawn line PX or QY is small extend it to intersect each other)

PQR is the required triangle

 

Posted by

Pankaj Sanodiya

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