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  • Corner points of the feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let Z = px+qy, where p, q > 0. Condition on p and q so that the minimum of Z occurs at (3, 0) and (1, 1) is A. p = 2q B. p = q/2 C. p = 3q D

Corner points of the feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let Z = px+qy , where p, q > 0. Condition on p and q so that the minimum of Z occurs at (3, 0) and (1, 1) is
A. p = 2q
B. p = q/2
C. p = 3q
D. p = q

Answers (1)

Given, Z = px+qy

Given, minimum occurs at (3, 0) and (1, 1).
For a minimum to occur at two points the value of Z at both points should be the same.
So, value of Z at (3, 0) = value of Z at (1, 1)
⇒ 3p = p + q
⇒ 2p = q

\Rightarrow p=\frac{q}{2}


So, option B is correct.

Posted by

infoexpert22

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