D is a point on side QR of \DeltaPQR such that PD \perp QR. Will it be correct to say that \DeltaPQD ~ \DeltaRPD? Why?

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D is a point on side QR of $\Delta$ PQR such that PD $\perp$ QR. Will it be correct to say that $\Delta$ PQD ~ $\Delta$ RPD? Why?

Answers (1)

Answer : [False]

In $\Delta$ PQD and $\Delta$ RPD

$PD = PD$ (common side)

$\angle PDQ = \angle PDR$ (each 90^o)

The given statement $\Delta PQD \sim \Delta RPD$ is false.

Because according to the definition of similarity two triangles are similar, if their corresponding angles are equal and their corresponding sides are in the same ratio

Posted by

infoexpert23

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D is a point on side QR of PQR such that PD QR. Will it be correct to say that PQD ~ RPD? Why?

Answers (1)

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D is a point on side QR of $\Delta$ PQR such that PD $\perp$ QR. Will it be correct to say that $\Delta$ PQD ~ $\Delta$ RPD? Why?