Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much ?

7. Dinesh went from place A to place B to place C. A is 7.5 km from B and B is 12.7 km from C.  Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?

 

Answers (1)

best_answer

Total distance travelled by Dinesh = AB + BC 

=  7.5km + 12.7km

= 20.2 km 

 Total distance travelled by Ayub = AD + DC 

= 9.3km + 11.8 km

=  21.1 km 

Hence Ayub travelled More distance than Ayub as 21.1 > 20.2

The difference between path travelled by them = 21.1km - 20.2 km 

= 0.9 km.

Hence Ayub travelled 0.9 km more than Dinesh.

Posted by

Pankaj Sanodiya

View full answer

Similar Questions

Trending Articles/News

anam-khan

JNVST Class 6 admit card 2025 out at navodaya.gov.in; exam in 2 phases
anam-khan

NVS LEST 2025 application correction deadline today at navodaya.gov.in; editable fields
anam-khan

NVS 2025 application correction window for Class 9, 11 admissions opens at navodaya.gov.in

Latest Question