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Electrode potential for Mg electrode varies according to the equation

E_{Mg^{2+}/Mg}=E^{\circleddash }_{Mg^{2+}/Mg}-\frac{0.0591}{2}\; log \frac{1}{[Mg^{2+}]} The graph of E_{Mg^{2+}/Mg} Vs log [Mg^{2+}] is

Answers (1)

The answer is the option (ii) E_{\frac{Mg2+}{Mg}}=E_{{\frac{Mg^{2+}}{Mg}}}^o-\frac{0.059}{2}log[Mg^{2+}]

The given equation is that of a straight line with a positive slope and a non-zero intercept

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