Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the equation of the circle with centre (1 / 2, 1 / 4) and radius 1 / 12

3.  Find the equation of the circle with

   centre \left(\frac{1}{2},\frac{1}{4} \right ) and radius \frac{1}{12}

 

Answers (1)

best_answer

As we know, 

The equation of the circle with centre ( h, k) and radius r is given by:

(x-h)^2+(y-k)^2=r^2

So, given here

(h,k)=\left ( \frac{1}{2},\frac{1}{4} \right ) 

AND 

 r=\frac{1}{12}

So, the equation of a circle is:

, \left ( x-\frac{1}{2}\right )^2+\left ( y-\frac{1}{4}\right )^2=\left ( \frac{1}{12}\right )^2

x^2-x+\frac{1}{4}+y^2-\frac{1}{2}y+\frac{1}{16}=\frac{1}{144}

x^2+y^2-x-\frac{1}{2}y-\frac{11}{36}=0

36x^2+36y^2-36x-18y-11=0

Posted by

Pankaj Sanodiya

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 Chemistry Exam Analysis 2025: Paper 'moderately difficult' but well balanced
anam-khan

CBSE Class 12 board exam still once a year; 20 lakh expected to appear in 2026 from February 17
anam-khan

CBSE board exams twice a year from 2025-26; 2 subject groups, 'better of two marks' in draft policy

Latest Question