Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the general solution of the following equation sec^22x is equal to 1 = tan2x

Q (8)  Find the general solution of the following equation 

   \small \sec^{2}2x = 1 - \tan2x

Answers (1)

best_answer

We know that 
\sec^{2}x = 1 + \tan^{2}x
So,
       1 + \tan^{2}2x = 1 -\tan2x
       \tan^{2}2x + \tan2x = 0\\ \\ \tan2x(\tan2x+1) = 0
 either
      tan2x = 0             or                     tan2x = -1                                                  (     \tan x = \tan \left ( \pi - \frac{\pi}{4} \right ) = \tan\frac{3\pi}{4} )
            2x = n\pi                       2x=n\pi + \frac{3\pi}{4}
               x=\frac{n\pi}{2}                        x=\frac{n\pi}{2} + \frac{3\pi}{8}
  Where n \epsilon Z

Posted by

seema garhwal

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exams 2025: Guidelines issued for Class 10, 12 practicals
anam-khan

Board Exam Date Sheet 2025 Live: ICSE, ISC, CBSE, MP time table out; BSEB routine soon
anam-khan

Board exam dates 2025: CBSE, CISCE, UP, MP, Maharashtra, TN time table out; state-wise updates

Latest Question