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Find the number of positive integers greater than 6000 and less than 7000 which are divisible by 5, provided that no digit is to be repeated.

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A number is divisible by 5, if at the unit place of the number there is 0 or 5. So, unit digit can be filled in 2 ways. Since, we have to form 4-digit numbers greater than 6000 and less than 7000. ‘6’ can fill the thousandth place only.

The hundredth and tenth place can be filled together in 8*7 =56 ways. So, total number of ways = 56*2 =112

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