Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the principal values of the following: 8. cot inverse of root 3

Find the principal values of the following:

    8. \cot^{-1}(\sqrt3)

Answers (1)

best_answer

Let us assume that \cot^{-1}(\sqrt3) = x , then we can write in other way,

\cot x = (\sqrt3)   or   

\cot (\frac{\pi}{6}) = (\sqrt3).

Hence when   x=\frac{\pi}{6}  we have \cot (\frac{\pi}{6}) = (\sqrt3).

and the range of principal values of \cot^{-1} lies in \left ( 0, \pi \right ).

Then the principal value of \cot^{-1}(\sqrt3) is \frac{\pi}{6}

 

Posted by

Divya Prakash Singh

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exams 2026: Online portal for availing CWSN facilities opens from September 9
anam-khan

CBSE announces deadline for Class 10, 12 direct admissions, subject change
anam-khan

CBSE warns about unauthorised sources offering ‘quick’ ways of getting duplicate marksheets, certificates

Latest Question