Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the value of k, if x - 1 is a factor of p(x) in the following case: (iii) kx ^2 - root 2 x + 1

3.(iii)  Find the value of k, if x - 1 is a factor of p(x) in the following case:

 (iii)    p(x) = kx^2-\sqrt2 x + 1

Answers (1)

best_answer

Zero of polynomial   x - 1 is  1

If  x - 1  is factor of polynomial   p(x) = kx^2-\sqrt2 x + 1

Then,  p(1)  must be equal to zero 

Now,

\Rightarrow p(1) = k(1)^2 -\sqrt2(1) + 1

\Rightarrow p(1) =0

\Rightarrow k -\sqrt2 +1= 0

\Rightarrow k = -1+\sqrt2

Therefore,  value of k is -1+\sqrt2

Posted by

Gautam harsolia

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exam 2025: Class 10, 12 practical exam dates out at cbse.gov.in; passing marks
anam-khan

CBSE urges schools to complete 100% registration of Class 9, 11 students by October 16; late fee for delays

Latest Question