Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

1. Find the value of the unknown x in the following diagram

Answers (1)

best_answer

As we know that the sum of the internal angles of the triangle is equal to $180^0$ . So,

i) $x+50^0+60^0=180^0$

$x=180^0-50^0-60^0$

$x=70^0$

ii) $x+30^0+90^0=180^0$

$x=180^0-30^0-90^0$

$x=60^0$

iii) $x+30^0+110^0=180^0$

$x=180^0-30^0-110^0$

$x=40^0$

iv) $x+x+50^0=180^0$

$2x=180^0-50^0$

$2x=130^0$

$x=65^0$

v) $x+x+x=180^0$

$3x=180^0$

$x=60^0$

vi) $x+2x^0+90^0=180^0$

$3x=180^0-90^0$

$3x=90^0$

$x=30^0$

Posted by

Pankaj Sanodiya

View full answer

Similar Questions

Trending Articles/News

anam-khan

JNVST Class 6 admit card 2025 out at navodaya.gov.in; exam in 2 phases

anam-khan

NVS LEST 2025 application correction deadline today at navodaya.gov.in; editable fields

anam-khan

NVS 2025 application correction window for Class 9, 11 admissions opens at navodaya.gov.in

Latest Question