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  • Formulate the following problems as a pair of equations, and hence find their solutions: (iii) Roohi travels 300 km to her home partly by train and partly by bus. She takes 4 hours if she travels 60 km by train and the remaining by bus. If she travels 100

Q2.    Formulate the following problems as a pair of equations, and hence find their solutions:

                (iii) Roohi travels 300 km to her home partly by train and partly by bus. She takes 4 hours if she travels 60 km by train and the remaining by bus. If she travels 100 km by train and the remaining by bus, she takes 10 minutes longer. Find the speed of the train and the bus separately.

Answers (1)

best_answer

Let the speed of the train and bus be u and v respectively

Now According to the question,

\frac{60}{u}+\frac{240}{v}=4

And

\frac{100}{u}+\frac{200}{v}=4+\frac{1}{6}

\Rightarrow \frac{100}{u}+\frac{200}{v}=\frac{25}{6}

Let, 

\frac{1}{u}=p\:and\:\frac{1}{v}=q

Now, our equation becomes

60p+140q=4

\Rightarrow 15p+60q=1.........(1)

And

100p+200q=\frac{25}{6}

\Rightarrow 4p+8q=\frac{1}{6}

\Rightarrow 24p+48q=1..........(2)

By Cross Multiplication method,

\frac{p}{b_1c_2-b_2c_1}=\frac{q}{c_1a_2-c_2a_1}=\frac{1}{a_1b_2-a_2b_1}

\frac{q}{(60)(-1)-(48)(-1)}=\frac{p}{(-1)(24)-(-1)(15)}=\frac{1}{(15)(48)-(60)(24)}

\frac{p}{-60+48}=\frac{q}{-24+15}=\frac{1}{720-1440}

\frac{p}{-12}=\frac{q}{-9}=\frac{1}{-720}

p=\frac{12}{720}=\frac{1}{60},\:and\:q=\frac{9}{720}=\frac{1}{80}

And Hence,

x=60\:and\:y=80

Hence the speed of the train and bus are 60 km/hour and 80 km/hour respectively.

Posted by

Pankaj Sanodiya

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