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  • If h = 10 cm, c = 6 cm, b = 12 cm, d = 4 cm, find the values of each of its parts separetely and add to find the area WXYZ.

Q2. If $\mathrm{h}=10 \mathrm{~cm}, \mathrm{c}=6 \mathrm{~cm}, \mathrm{~b}=12 \mathrm{~cm}, \mathrm{~d}=4 \mathrm{~cm}$, find the values of each of its parts separately and add to find the area $WXYZ$. Verify it by putting the values of h, a and b in the expression $\frac{h(a+b)}{2}$

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Area of trapezium $WXYZ$ = Area of triangle with base'c'+area of rectangle +area of triangle with base 'd'

$ =\left(\frac{1}{2} \times c \times h\right)+(b \times h)+\left(\frac{1}{2} \times d \times h\right)$

$=\left(\frac{1}{2} \times 6 \times 10\right)+(12 \times 10)+\left(\frac{1}{2} \times 4 \times 10\right)$

$=(30)+(120)+(20)$

$=170 \mathrm{~cm}^2$

The area $WXYZ$ by the expression $\frac{h(a+b)}{2}$

$=\frac{10(22+12)}{2}$

$=\frac{10(34)}{2}$

$=10 \times 17$

$=170 \mathrm{~cm}^2$

Hence, we can conclude area from the given expression and the calculated area is equal.

Posted by

seema garhwal

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