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If one of the zeroes of the quadratic polynomial  (k-1) x^2 + kx + 1is –3, then the value of k is

(A) \frac{4}{3}

(B) \frac{-4}{3}

(C) \frac{2}{3}

(D) \frac{-2}{3}

Answers (1)

Answer. [A]

Solution.  Polynomial : It is an expression of more than two algebraic terms, especially the sum of several terms that contains different powers of the same variable(s) and a quadratic polynomial is polynomial of degree 2.

Let p(x) = (k - 1)x^2 + kx + 1

If –3 is one of the zeroes of p(x) then p(–3) = 0

put x = –3 in p(x)

p(-3) = (k - 1) (-3)^2 + k(-3) + 1

0 = (k - 1) (9) -3k + 1

0 = 9k - 9 - 3k + 1

0 = 6k - 8

6k = 8

k =\frac{8}{6}

k =\frac{4}{3}

 

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