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  • If the first term of an AP is –5 and the common difference is 2, then the sum of the first 6 terms is (A) 0 (B) 5 (C) 6 (D) 15

If the first term of an AP is –5 and the common difference is 2, then the sum of the first 6 terms is

(A) 0

(B) 5

(C) 6

(D) 15

Answers (1)

\\$Given a=-5,d=2 here a= first term and d= common difference\\$ S\textsubscript{6} = \frac{6}{2}(2a+(6-1)d) \\ = 3(2 \times (-5) + 5 \times 2)\\ = 3(-10 + 10)\\ = 3(0) = 0\\

Hence option A is correct

Posted by

infoexpert21

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