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If the focus of a parabola is (0, –3) and its directrix is y = 3, then its equation is
A. x2 = –12y
B. x2 = 12y
C. y2 = –12x
D. y= 12x

Answers (1)

a Given that, focus of parabola is at S(0,-3)and equation of directrix is y=3 

 For any point P(x,y)on the parabola, we have

 SP=PM

\sqrt{(x-0)^{2}+(y+3)^{2}}=\left | y-3 \right |

x2+y2+6y+9=y2-6y+9

x2=-12y

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