Q: If the sum of the distances of a moving point in a plane from the axes is 1, then find the locus of the point
Let the coordinates of a moving point $P$ be $(a,b)$
It is given that the sum of the distance from the axes to the point is always 1,
$|x|+|y|=1$
$±x±y=1$,
$\implies -x-y=1$, $x+y=1$, $-x+y=1$ and $x-y=1$
Hence, these equations gives us the locus of the point P which is a square.