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Q: If the sum of the distances of a moving point in a plane from the axes is 1, then find the locus of the point

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Let the coordinates of a moving point $P$ be $(a,b)$

It is given that the sum of the distance from the axes to the point is always 1,

$|x|+|y|=1$ 

$±x±y=1$,

$\implies -x-y=1$, $x+y=1$, $-x+y=1$ and $x-y=1$

Hence, these equations gives us the locus of the point P which is a square.

 

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