Get Answers to all your Questions

header-bg qa

In a potato race 20 potatoes are placed in a line at intervals of 4 metres with the first potato 24 metres from the starting point. A contestant is required to bring the potatoes back to the starting place one at a time. How far would he run in bringing back all the potatoes?

Answers (1)

It is given that at start he has to run 24m to get the first potato then 28 m as the next potato is 4m away and so on.

Hence, the sequence of its running will be 24, 28, 32…..

To get potatoes from the starting point he has to run  24+ 28+ 32+….. up to 20 terms

\\S_{n}= \left( \frac{n}{2} \right) \left( 2a+ \left( n-1 \right) d \right) \\\\ S_{20}= \left( \frac{20}{2} \right) \left( 2 \left( 24 \right) + \left( 20-1 \right) 4 \right) \\\\ S_{20}=10 \left( 48+76 \right) \\\\ S_{20}=1240m \\\\

 

Also, he has to get the potato back to the starting point hence the total distance will be twice

Total Distance ran=2×1240=2480m

 

Posted by

infoexpert21

View full answer